Solve [-3+5*(-2)-(-28):(-2)^2-(-6-2)]*(-1)

$$[ - 3 + 5 \cdot ( - 2 ) - ( - 28 ) : ( - 2 ) ^ { 2 } - ( - 6 - 2 ) ] \cdot ( - 1 )$$

Evaluate

$$-2$$

Solution Steps

Multiply 5 and -2 to get -10.

$$\left(-3-10-\frac{-28}{\left(-2\right)^{2}}-\left(-6-2\right)\right)\left(-1\right)$$

Subtract 10 from -3 to get -13.

$$\left(-13-\frac{-28}{\left(-2\right)^{2}}-\left(-6-2\right)\right)\left(-1\right)$$

Calculate -2 to the power of 2 and get 4.

$$\left(-13-\frac{-28}{4}-\left(-6-2\right)\right)\left(-1\right)$$

Divide -28 by 4 to get -7.

$$\left(-13-\left(-7\right)-\left(-6-2\right)\right)\left(-1\right)$$

The opposite of -7 is 7.

$$\left(-13+7-\left(-6-2\right)\right)\left(-1\right)$$

Add -13 and 7 to get -6.

$$\left(-6-\left(-6-2\right)\right)\left(-1\right)$$

Subtract 2 from -6 to get -8.

$$\left(-6-\left(-8\right)\right)\left(-1\right)$$

The opposite of -8 is 8.

$$\left(-6+8\right)\left(-1\right)$$

Add -6 and 8 to get 2.

$$2\left(-1\right)$$

Multiply 2 and -1 to get -2.

$$-2$$

Factor

$$-2$$