Solve [-2*(2*3-7)^2+3]*(1-10)

$$[ - 2 \cdot ( 2 \cdot 3 - 7 ) ^ { 2 } + 3 ] \cdot ( 1 - 10 )$$

Evaluate

$$-9$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(-2\left(6-7\right)^{2}+3\right)\left(1-10\right)$$

Subtract 7 from 6 to get -1.

$$\left(-2\left(-1\right)^{2}+3\right)\left(1-10\right)$$

Calculate -1 to the power of 2 and get 1.

$$\left(-2+3\right)\left(1-10\right)$$

Add -2 and 3 to get 1.

$$1\left(1-10\right)$$

Subtract 10 from 1 to get -9.

$$1\left(-9\right)$$

Multiply 1 and -9 to get -9.

$$-9$$

Factor

$$-9$$