Solve [-2^{-3}-8^-1*(-1)^-2]*(-1/2)^-2*7^0

$$[ - 2 ^ { - 3 } - 8 ^ { - 1 } \times ( - 1 ) ^ { - 2 } ] \times ( - \frac { 1 } { 2 } ) ^ { - 2 } \times 7 ^ { 0 }$$

Evaluate

$$-1$$

Solution Steps

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\left(-\frac{1}{8}-8^{-1}\left(-1\right)^{-2}\right)\left(-\frac{1}{2}\right)^{-2}\times 7^{0}$$

Calculate 8 to the power of -1 and get \frac{1}{8}.

$$\left(-\frac{1}{8}-\frac{1}{8}\left(-1\right)^{-2}\right)\left(-\frac{1}{2}\right)^{-2}\times 7^{0}$$

Calculate -1 to the power of -2 and get 1.

$$\left(-\frac{1}{8}-\frac{1}{8}\times 1\right)\left(-\frac{1}{2}\right)^{-2}\times 7^{0}$$

Multiply \frac{1}{8} and 1 to get \frac{1}{8}.

$$\left(-\frac{1}{8}-\frac{1}{8}\right)\left(-\frac{1}{2}\right)^{-2}\times 7^{0}$$

Subtract \frac{1}{8} from -\frac{1}{8} to get -\frac{1}{4}.

$$-\frac{1}{4}\left(-\frac{1}{2}\right)^{-2}\times 7^{0}$$

Calculate -\frac{1}{2} to the power of -2 and get 4.

$$-\frac{1}{4}\times 4\times 7^{0}$$

Multiply -\frac{1}{4} and 4 to get -1.

$$-7^{0}$$

Calculate 7 to the power of 0 and get 1.

$$-1$$

Factor

$$-1$$