Solve [-2+3(2-5)div3]-[(3-5+2)-2(3-4)]

$$[ - 2 + 3 ( 2 - 5 ) \div 3 ] - [ ( 3 - 5 + 2 ) - 2 ( 3 - 4 ) ]$$

Evaluate

$$-7$$

Solution Steps

Cancel out 3 and 3.

$$-2+2-5-\left(3-5+2-2\left(3-4\right)\right)$$

Subtract 5 from 2 to get -3.

$$-2-3-\left(3-5+2-2\left(3-4\right)\right)$$

Subtract 3 from -2 to get -5.

$$-5-\left(3-5+2-2\left(3-4\right)\right)$$

Subtract 5 from 3 to get -2.

$$-5-\left(-2+2-2\left(3-4\right)\right)$$

Add -2 and 2 to get 0.

$$-5-\left(0-2\left(3-4\right)\right)$$

Subtract 4 from 3 to get -1.

$$-5-\left(0-2\left(-1\right)\right)$$

Multiply 2 and -1 to get -2.

$$-5-\left(0-\left(-2\right)\right)$$

The opposite of -2 is 2.

$$-5-\left(0+2\right)$$

Add 0 and 2 to get 2.

$$-5-2$$

Subtract 2 from -5 to get -7.

$$-7$$

Factor

$$-7$$