Solve [-[-(-4+2*3+1)]*3-2*[-(-6-6div2*3+1)]-1]=

$$[ - [ - ( - 4 + 2 \times 3 + 1 ) ] \times 3 - 2 \times [ - ( - 6 - 6 \div 2 \times 3 + 1 ) ] - 1 ] =$$

Evaluate

$$-20$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\left(-\left(-\left(-4+6+1\right)\right)\right)\times 3-2\left(-\left(-6-\frac{6}{2}\times 3+1\right)\right)-1$$

Add -4 and 6 to get 2.

$$\left(-\left(-\left(2+1\right)\right)\right)\times 3-2\left(-\left(-6-\frac{6}{2}\times 3+1\right)\right)-1$$

Add 2 and 1 to get 3.

$$\left(-\left(-3\right)\right)\times 3-2\left(-\left(-6-\frac{6}{2}\times 3+1\right)\right)-1$$

The opposite of -3 is 3.

$$3\times 3-2\left(-\left(-6-\frac{6}{2}\times 3+1\right)\right)-1$$

Multiply 3 and 3 to get 9.

$$9-2\left(-\left(-6-\frac{6}{2}\times 3+1\right)\right)-1$$

Divide 6 by 2 to get 3.

$$9-2\left(-\left(-6-3\times 3+1\right)\right)-1$$

Multiply 3 and 3 to get 9.

$$9-2\left(-\left(-6-9+1\right)\right)-1$$

Subtract 9 from -6 to get -15.

$$9-2\left(-\left(-15+1\right)\right)-1$$

Add -15 and 1 to get -14.

$$9-2\left(-\left(-14\right)\right)-1$$

The opposite of -14 is 14.

$$9-2\times 14-1$$

Multiply 2 and 14 to get 28.

$$9-28-1$$

Subtract 28 from 9 to get -19.

$$-19-1$$

Subtract 1 from -19 to get -20.

$$-20$$

Factor

$$-20$$