Solve [(xy)^{2}*x-2x^{3}y^{2}]:(-x^{2})+[2x^{2}y^{3}+(-3x^{4}y^{5}):(-1/2xy)^2]:[(-3x^3y^3):(2xy)^2+2xy]

$$[ ( x y ) ^ { 2 } \cdot x - 2 x ^ { 3 } y ^ { 2 } ] : ( - x ^ { 2 } ) + [ 2 x ^ { 2 } y ^ { 3 } + ( - 3 x ^ { 4 } y ^ { 5 } ) : ( - \frac { 1 } { 2 } x y ) ^ { 2 } ] : [ ( - 3 x ^ { 3 } y ^ { 3 } ) : ( 2 x y ) ^ { 2 } + 2 x y ]$$

Evaluate

$$-7xy^{2}$$

Short Solution Steps

Expand \left(xy\right)^{2}.

$$\frac{x^{2}y^{2}x-2x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}xy\right)^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{x^{3}y^{2}-2x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}xy\right)^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Combine x^{3}y^{2} and -2x^{3}y^{2} to get -x^{3}y^{2}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}xy\right)^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Expand \left(-\frac{1}{2}xy\right)^{2}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}\right)^{2}x^{2}y^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\frac{1}{4}x^{2}y^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Cancel out x^{2}y^{2} in both numerator and denominator.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{2}y^{3}}{\frac{1}{4}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Divide -3x^{2}y^{3} by \frac{1}{4} by multiplying -3x^{2}y^{3} by the reciprocal of \frac{1}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Expand \left(2xy\right)^{2}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3x^{3}y^{3}}{2^{2}x^{2}y^{2}}+2xy}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3x^{3}y^{3}}{4x^{2}y^{2}}+2xy}$$

Cancel out x^{2}y^{2} in both numerator and denominator.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy}{4}+2xy}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2xy times \frac{4}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy}{4}+\frac{4\times 2xy}{4}}$$

Since \frac{-3xy}{4} and \frac{4\times 2xy}{4} have the same denominator, add them by adding their numerators.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy+4\times 2xy}{4}}$$

Do the multiplications in -3xy+4\times 2xy.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy+8xy}{4}}$$

Combine like terms in -3xy+8xy.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{5xy}{4}}$$

Multiply -3 and 4 to get -12.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-12x^{2}y^{3}}{\frac{5xy}{4}}$$

Combine 2x^{2}y^{3} and -12x^{2}y^{3} to get -10x^{2}y^{3}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{-10x^{2}y^{3}}{\frac{5xy}{4}}$$

Divide -10x^{2}y^{3} by \frac{5xy}{4} by multiplying -10x^{2}y^{3} by the reciprocal of \frac{5xy}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{-10x^{2}y^{3}\times 4}{5xy}$$

Cancel out 5xy in both numerator and denominator.

$$\frac{-x^{3}y^{2}}{-x^{2}}-2\times 4xy^{2}$$

Multiply -2 and 4 to get -8.

$$\frac{-x^{3}y^{2}}{-x^{2}}-8xy^{2}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -8xy^{2} times \frac{-x^{2}}{-x^{2}}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{-8xy^{2}\left(-1\right)x^{2}}{-x^{2}}$$

Since \frac{-x^{3}y^{2}}{-x^{2}} and \frac{-8xy^{2}\left(-1\right)x^{2}}{-x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{-x^{3}y^{2}-8xy^{2}\left(-1\right)x^{2}}{-x^{2}}$$

Do the multiplications in -x^{3}y^{2}-8xy^{2}\left(-1\right)x^{2}.

$$\frac{-x^{3}y^{2}+8x^{3}y^{2}}{-x^{2}}$$

Combine like terms in -x^{3}y^{2}+8x^{3}y^{2}.

$$\frac{7x^{3}y^{2}}{-x^{2}}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{7xy^{2}}{-1}$$

Expand

$$-7xy^{2}$$

Short Solution Steps

Expand \left(xy\right)^{2}.

$$\frac{x^{2}y^{2}x-2x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}xy\right)^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{x^{3}y^{2}-2x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}xy\right)^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Combine x^{3}y^{2} and -2x^{3}y^{2} to get -x^{3}y^{2}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}xy\right)^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Expand \left(-\frac{1}{2}xy\right)^{2}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\left(-\frac{1}{2}\right)^{2}x^{2}y^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{4}y^{5}}{\frac{1}{4}x^{2}y^{2}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Cancel out x^{2}y^{2} in both numerator and denominator.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}+\frac{-3x^{2}y^{3}}{\frac{1}{4}}}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Divide -3x^{2}y^{3} by \frac{1}{4} by multiplying -3x^{2}y^{3} by the reciprocal of \frac{1}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3x^{3}y^{3}}{\left(2xy\right)^{2}}+2xy}$$

Expand \left(2xy\right)^{2}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3x^{3}y^{3}}{2^{2}x^{2}y^{2}}+2xy}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3x^{3}y^{3}}{4x^{2}y^{2}}+2xy}$$

Cancel out x^{2}y^{2} in both numerator and denominator.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy}{4}+2xy}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2xy times \frac{4}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy}{4}+\frac{4\times 2xy}{4}}$$

Since \frac{-3xy}{4} and \frac{4\times 2xy}{4} have the same denominator, add them by adding their numerators.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy+4\times 2xy}{4}}$$

Do the multiplications in -3xy+4\times 2xy.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{-3xy+8xy}{4}}$$

Combine like terms in -3xy+8xy.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-3x^{2}y^{3}\times 4}{\frac{5xy}{4}}$$

Multiply -3 and 4 to get -12.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{2x^{2}y^{3}-12x^{2}y^{3}}{\frac{5xy}{4}}$$

Combine 2x^{2}y^{3} and -12x^{2}y^{3} to get -10x^{2}y^{3}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{-10x^{2}y^{3}}{\frac{5xy}{4}}$$

Divide -10x^{2}y^{3} by \frac{5xy}{4} by multiplying -10x^{2}y^{3} by the reciprocal of \frac{5xy}{4}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{-10x^{2}y^{3}\times 4}{5xy}$$

Cancel out 5xy in both numerator and denominator.

$$\frac{-x^{3}y^{2}}{-x^{2}}-2\times 4xy^{2}$$

Multiply -2 and 4 to get -8.

$$\frac{-x^{3}y^{2}}{-x^{2}}-8xy^{2}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply -8xy^{2} times \frac{-x^{2}}{-x^{2}}.

$$\frac{-x^{3}y^{2}}{-x^{2}}+\frac{-8xy^{2}\left(-1\right)x^{2}}{-x^{2}}$$

Since \frac{-x^{3}y^{2}}{-x^{2}} and \frac{-8xy^{2}\left(-1\right)x^{2}}{-x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{-x^{3}y^{2}-8xy^{2}\left(-1\right)x^{2}}{-x^{2}}$$

Do the multiplications in -x^{3}y^{2}-8xy^{2}\left(-1\right)x^{2}.

$$\frac{-x^{3}y^{2}+8x^{3}y^{2}}{-x^{2}}$$

Combine like terms in -x^{3}y^{2}+8x^{3}y^{2}.

$$\frac{7x^{3}y^{2}}{-x^{2}}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{7xy^{2}}{-1}$$