Solve [(9^2)^5*9^3]div9^9

$$[ ( 9 ^ { 2 } ) ^ { 5 } \times 9 ^ { 3 } ] \div 9 ^ { 9 }$$

Evaluate

$$6561$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 5 to get 10.

$$\frac{9^{10}\times 9^{3}}{9^{9}}$$

To multiply powers of the same base, add their exponents. Add 10 and 3 to get 13.

$$\frac{9^{13}}{9^{9}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 9 from 13 to get 4.

$$9^{4}$$

Calculate 9 to the power of 4 and get 6561.

$$6561$$

Factor

$$3^{8}$$