Solve [(9^0.5+3)*2^3]*3^-2

$$[ ( 9 ^ { 0.5 } + 3 ) \cdot 2 ^ { 3 } ] \cdot 3 ^ { - 2 }$$

Evaluate

$$\frac{16}{3}\approx 5.333333333$$

Solution Steps

Calculate 9 to the power of 0.5 and get 3.

$$\left(3+3\right)\times 2^{3}\times 3^{-2}$$

Add 3 and 3 to get 6.

$$6\times 2^{3}\times 3^{-2}$$

Calculate 2 to the power of 3 and get 8.

$$6\times 8\times 3^{-2}$$

Multiply 6 and 8 to get 48.

$$48\times 3^{-2}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$48\times \frac{1}{9}$$

Multiply 48 and \frac{1}{9} to get \frac{16}{3}.

$$\frac{16}{3}$$

Factor

$$\frac{2 ^ {4}}{3} = 5\frac{1}{3} = 5.333333333333333$$