Solve [(8*4+3)div7+(3+15div5)*3]*2-(19-7)div6}*2+12=

$$[ ( 8 \cdot 4 + 3 ) \div 7 + ( 3 + 15 \div 5 ) \cdot 3 ] \cdot 2 - ( 19 - 7 ) \div 6 \} \cdot 2 + 12 =$$

Evaluate

$$44$$

Solution Steps

Multiply 8 and 4 to get 32.

$$\left(\frac{32+3}{7}+\left(3+\frac{15}{5}\right)\times 3\right)\times 2-\frac{19-7}{6}$$

Add 32 and 3 to get 35.

$$\left(\frac{35}{7}+\left(3+\frac{15}{5}\right)\times 3\right)\times 2-\frac{19-7}{6}$$

Divide 35 by 7 to get 5.

$$\left(5+\left(3+\frac{15}{5}\right)\times 3\right)\times 2-\frac{19-7}{6}$$

Divide 15 by 5 to get 3.

$$\left(5+\left(3+3\right)\times 3\right)\times 2-\frac{19-7}{6}$$

Add 3 and 3 to get 6.

$$\left(5+6\times 3\right)\times 2-\frac{19-7}{6}$$

Multiply 6 and 3 to get 18.

$$\left(5+18\right)\times 2-\frac{19-7}{6}$$

Add 5 and 18 to get 23.

$$23\times 2-\frac{19-7}{6}$$

Multiply 23 and 2 to get 46.

$$46-\frac{19-7}{6}$$

Subtract 7 from 19 to get 12.

$$46-\frac{12}{6}$$

Divide 12 by 6 to get 2.

$$46-2$$

Subtract 2 from 46 to get 44.

$$44$$

Factor

$$2^{2}\times 11$$