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\left(7b\right)^{2}-9-9-49b^{2}+18
Consider \left(7b+3\right)\left(7b-3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 3.
7^{2}b^{2}-9-9-49b^{2}+18
Expand \left(7b\right)^{2}.
49b^{2}-9-9-49b^{2}+18
Calculate 7 to the power of 2 and get 49.
49b^{2}-18-49b^{2}+18
Subtract 9 from -9 to get -18.
-18+18
Combine 49b^{2} and -49b^{2} to get 0.
0
Add -18 and 18 to get 0.
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