Solve [(40div10)-5]+[(sqrt{36}*1^2)3]

$$[ ( 40 \div 10 ) - 5 ] + [ ( \sqrt { 36 } \times 1 ^ { 2 } ) 3 ]$$

Evaluate

$$17$$

Solution Steps

Divide 40 by 10 to get 4.

$$4-5+3\sqrt{36}\times 1^{2}$$

Subtract 5 from 4 to get -1.

$$-1+3\sqrt{36}\times 1^{2}$$

Calculate the square root of 36 and get 6.

$$-1+3\times 6\times 1^{2}$$

Multiply 3 and 6 to get 18.

$$-1+18\times 1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$-1+18\times 1$$

Multiply 18 and 1 to get 18.

$$-1+18$$

Add -1 and 18 to get 17.

$$17$$

Factor

$$17$$