Solve [(30+3*2)div8+5*4]div6=

$$[ ( 30 + 3 \cdot 2 ) \div 8 + 5 \cdot 4 ] \div 6 =$$

Evaluate

$$\frac{49}{12}\approx 4.083333333$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\frac{\frac{30+6}{8}+5\times 4}{6}$$

Add 30 and 6 to get 36.

$$\frac{\frac{36}{8}+5\times 4}{6}$$

Reduce the fraction \frac{36}{8} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{9}{2}+5\times 4}{6}$$

Multiply 5 and 4 to get 20.

$$\frac{\frac{9}{2}+20}{6}$$

Convert 20 to fraction \frac{40}{2}.

$$\frac{\frac{9}{2}+\frac{40}{2}}{6}$$

Since \frac{9}{2} and \frac{40}{2} have the same denominator, add them by adding their numerators.

$$\frac{\frac{9+40}{2}}{6}$$

Add 9 and 40 to get 49.

$$\frac{\frac{49}{2}}{6}$$

Express \frac{\frac{49}{2}}{6} as a single fraction.

$$\frac{49}{2\times 6}$$

Multiply 2 and 6 to get 12.

$$\frac{49}{12}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {2} \cdot 3} = 4\frac{1}{12} = 4.083333333333333$$