Solve [(29+69+25*12+2)-25*(4*27-4*25)]:{[(5*12-2)-18]-30}

$$[ ( 29 + 69 + 25 \cdot 12 + 2 ) - 25 \cdot ( 4 \cdot 27 - 4 \cdot 25 ) ] : \{ [ ( 5 \cdot 12 - 2 ) - 18 ] - 30 \}$$

Evaluate

$$20$$

Solution Steps

Add 29 and 69 to get 98.

$$\frac{98+25\times 12+2-25\left(4\times 27-4\times 25\right)}{5\times 12-2-18-30}$$

Multiply 25 and 12 to get 300.

$$\frac{98+300+2-25\left(4\times 27-4\times 25\right)}{5\times 12-2-18-30}$$

Add 98 and 300 to get 398.

$$\frac{398+2-25\left(4\times 27-4\times 25\right)}{5\times 12-2-18-30}$$

Add 398 and 2 to get 400.

$$\frac{400-25\left(4\times 27-4\times 25\right)}{5\times 12-2-18-30}$$

Multiply 4 and 27 to get 108.

$$\frac{400-25\left(108-4\times 25\right)}{5\times 12-2-18-30}$$

Multiply 4 and 25 to get 100.

$$\frac{400-25\left(108-100\right)}{5\times 12-2-18-30}$$

Subtract 100 from 108 to get 8.

$$\frac{400-25\times 8}{5\times 12-2-18-30}$$

Multiply 25 and 8 to get 200.

$$\frac{400-200}{5\times 12-2-18-30}$$

Subtract 200 from 400 to get 200.

$$\frac{200}{5\times 12-2-18-30}$$

Multiply 5 and 12 to get 60.

$$\frac{200}{60-2-18-30}$$

Subtract 2 from 60 to get 58.

$$\frac{200}{58-18-30}$$

Subtract 18 from 58 to get 40.

$$\frac{200}{40-30}$$

Subtract 30 from 40 to get 10.

$$\frac{200}{10}$$

Divide 200 by 10 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$