Solve [(2)-2a+3b)(2a+3b)

$$[ ( 2 ) - 2 a + 3 b ) ( 2 a + 3 b )$$

Evaluate

$$\left(2a+3b\right)\left(2+3b-2a\right)$$

Solution Steps

Apply the distributive property by multiplying each term of 2-2a+3b by each term of 2a+3b.

$$4a+6b-4a^{2}-6ab+6ba+9b^{2}$$

Combine -6ab and 6ba to get 0.

$$4a+6b-4a^{2}+9b^{2}$$

Expand

$$6b+9b^{2}+4a-4a^{2}$$

Solution Steps

Apply the distributive property by multiplying each term of 2-2a+3b by each term of 2a+3b.

$$4a+6b-4a^{2}-6ab+6ba+9b^{2}$$

Combine -6ab and 6ba to get 0.

$$4a+6b-4a^{2}+9b^{2}$$