Solve [(2*3)+(5-7)]div2+(2*4)*6+8)

$$[ ( 2 \times 3 ) + ( 5 - 7 ) ] \div 2 + ( 2 \times 4 ) \cdot 6 + 8 )$$

Evaluate

$$58$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+5-7}{2}+2\times 4\times 6+8$$

Add 6 and 5 to get 11.

$$\frac{11-7}{2}+2\times 4\times 6+8$$

Subtract 7 from 11 to get 4.

$$\frac{4}{2}+2\times 4\times 6+8$$

Divide 4 by 2 to get 2.

$$2+2\times 4\times 6+8$$

Multiply 2 and 4 to get 8.

$$2+8\times 6+8$$

Multiply 8 and 6 to get 48.

$$2+48+8$$

Add 2 and 48 to get 50.

$$50+8$$

Add 50 and 8 to get 58.

$$58$$

Factor

$$2\times 29$$