Solve [(2^3)^2*2^8]div2^10

$$[ ( 2 ^ { 3 } ) ^ { 2 } \times 2 ^ { 8 } ] \div 2 ^ { 10 }$$

Evaluate

$$16$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 2 to get 6.

$$\frac{2^{6}\times 2^{8}}{2^{10}}$$

To multiply powers of the same base, add their exponents. Add 6 and 8 to get 14.

$$\frac{2^{14}}{2^{10}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 10 from 14 to get 4.

$$2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$16$$

Factor

$$2^{4}$$