Solve [(2^{3}*5-2^{3}*3):2^3+7]^3:3^3-5^2

$$[ ( 2 ^ { 3 } \times 5 - 2 ^ { 3 } \times 3 ) : 2 ^ { 3 } + 7 ] ^ { 3 } : 3 ^ { 3 } - 5 ^ { 2 }$$

Evaluate

$$2$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{\left(\frac{8\times 5-2^{3}\times 3}{2^{3}}+7\right)^{3}}{3^{3}}-5^{2}$$

Multiply 8 and 5 to get 40.

$$\frac{\left(\frac{40-2^{3}\times 3}{2^{3}}+7\right)^{3}}{3^{3}}-5^{2}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{\left(\frac{40-8\times 3}{2^{3}}+7\right)^{3}}{3^{3}}-5^{2}$$

Multiply 8 and 3 to get 24.

$$\frac{\left(\frac{40-24}{2^{3}}+7\right)^{3}}{3^{3}}-5^{2}$$

Subtract 24 from 40 to get 16.

$$\frac{\left(\frac{16}{2^{3}}+7\right)^{3}}{3^{3}}-5^{2}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{\left(\frac{16}{8}+7\right)^{3}}{3^{3}}-5^{2}$$

Divide 16 by 8 to get 2.

$$\frac{\left(2+7\right)^{3}}{3^{3}}-5^{2}$$

Add 2 and 7 to get 9.

$$\frac{9^{3}}{3^{3}}-5^{2}$$

Calculate 9 to the power of 3 and get 729.

$$\frac{729}{3^{3}}-5^{2}$$

Calculate 3 to the power of 3 and get 27.

$$\frac{729}{27}-5^{2}$$

Divide 729 by 27 to get 27.

$$27-5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$27-25$$

Subtract 25 from 27 to get 2.

$$2$$

Factor

$$2$$