Solve [(2+2^{3})-(64-2^{2})*2^4]^2+(8-18:3^2)^2=

$$[ ( 2 + 2 ^ { 3 } ) - ( 64 - 2 ^ { 2 } ) \cdot 2 ^ { 4 } ] ^ { 2 } + ( 8 - 18 : 3 ^ { 2 } ) ^ { 2 } =$$

Evaluate

$$902536$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\left(2+8-\left(64-2^{2}\right)\times 2^{4}\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Add 2 and 8 to get 10.

$$\left(10-\left(64-2^{2}\right)\times 2^{4}\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$\left(10-\left(64-4\right)\times 2^{4}\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Subtract 4 from 64 to get 60.

$$\left(10-60\times 2^{4}\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Calculate 2 to the power of 4 and get 16.

$$\left(10-60\times 16\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Multiply 60 and 16 to get 960.

$$\left(10-960\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Subtract 960 from 10 to get -950.

$$\left(-950\right)^{2}+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Calculate -950 to the power of 2 and get 902500.

$$902500+\left(8-\frac{18}{3^{2}}\right)^{2}$$

Calculate 3 to the power of 2 and get 9.

$$902500+\left(8-\frac{18}{9}\right)^{2}$$

Divide 18 by 9 to get 2.

$$902500+\left(8-2\right)^{2}$$

Subtract 2 from 8 to get 6.

$$902500+6^{2}$$

Calculate 6 to the power of 2 and get 36.

$$902500+36$$

Add 902500 and 36 to get 902536.

$$902536$$

Factor

$$2^{3}\times 101\times 1117$$