Solve [(1-9/10)div3/5]*6/7

$$[ ( 1 - \frac { 9 } { 10 } ) \div \frac { 3 } { 5 } ] \times \frac { 6 } { 7 }$$

Evaluate

$$\frac{1}{7}\approx 0.142857143$$

Solution Steps

Convert 1 to fraction \frac{10}{10}.

$$\frac{\frac{10}{10}-\frac{9}{10}}{\frac{3}{5}}\times \frac{6}{7}$$

Since \frac{10}{10} and \frac{9}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{10-9}{10}}{\frac{3}{5}}\times \frac{6}{7}$$

Subtract 9 from 10 to get 1.

$$\frac{\frac{1}{10}}{\frac{3}{5}}\times \frac{6}{7}$$

Divide \frac{1}{10} by \frac{3}{5} by multiplying \frac{1}{10} by the reciprocal of \frac{3}{5}.

$$\frac{1}{10}\times \frac{5}{3}\times \frac{6}{7}$$

Multiply \frac{1}{10} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 5}{10\times 3}\times \frac{6}{7}$$

Do the multiplications in the fraction \frac{1\times 5}{10\times 3}.

$$\frac{5}{30}\times \frac{6}{7}$$

Reduce the fraction \frac{5}{30} to lowest terms by extracting and canceling out 5.

$$\frac{1}{6}\times \frac{6}{7}$$

Multiply \frac{1}{6} times \frac{6}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 6}{6\times 7}$$

Cancel out 6 in both numerator and denominator.

$$\frac{1}{7}$$

Factor

$$\frac{1}{7} = 0.14285714285714285$$