Solve [(1-1/3)^2+(1-1/9)]:(2-1/3)=

$$[ ( 1 - \frac { 1 } { 3 } ) ^ { 2 } + ( 1 - \frac { 1 } { 9 } ) ] : ( 2 - \frac { 1 } { 3 } ) =$$

Evaluate

$$\frac{4}{5}=0.8$$

Solution Steps

Subtract \frac{1}{3} from 1 to get \frac{2}{3}.

$$\frac{\left(\frac{2}{3}\right)^{2}+1-\frac{1}{9}}{2-\frac{1}{3}}$$

Calculate \frac{2}{3} to the power of 2 and get \frac{4}{9}.

$$\frac{\frac{4}{9}+1-\frac{1}{9}}{2-\frac{1}{3}}$$

Add \frac{4}{9} and 1 to get \frac{13}{9}.

$$\frac{\frac{13}{9}-\frac{1}{9}}{2-\frac{1}{3}}$$

Subtract \frac{1}{9} from \frac{13}{9} to get \frac{4}{3}.

$$\frac{\frac{4}{3}}{2-\frac{1}{3}}$$

Subtract \frac{1}{3} from 2 to get \frac{5}{3}.

$$\frac{\frac{4}{3}}{\frac{5}{3}}$$

Divide \frac{4}{3} by \frac{5}{3} by multiplying \frac{4}{3} by the reciprocal of \frac{5}{3}.

$$\frac{4}{3}\times \frac{3}{5}$$

Multiply \frac{4}{3} and \frac{3}{5} to get \frac{4}{5}.

$$\frac{4}{5}$$

Factor

$$\frac{2 ^ {2}}{5} = 0.8$$