Solve [(-6)*(-5+2)-(-3)]*(-2)+(5-9)^2

$$[ ( - 6 ) \cdot ( - 5 + 2 ) - ( - 3 ) ] \cdot ( - 2 ) + ( 5 - 9 ) ^ { 2 }$$

Evaluate

$$-26$$

Solution Steps

Add -5 and 2 to get -3.

$$\left(-6\left(-3\right)-\left(-3\right)\right)\left(-2\right)+\left(5-9\right)^{2}$$

Multiply -6 and -3 to get 18.

$$\left(18-\left(-3\right)\right)\left(-2\right)+\left(5-9\right)^{2}$$

The opposite of -3 is 3.

$$\left(18+3\right)\left(-2\right)+\left(5-9\right)^{2}$$

Add 18 and 3 to get 21.

$$21\left(-2\right)+\left(5-9\right)^{2}$$

Multiply 21 and -2 to get -42.

$$-42+\left(5-9\right)^{2}$$

Subtract 9 from 5 to get -4.

$$-42+\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$-42+16$$

Add -42 and 16 to get -26.

$$-26$$

Factor

$$-26$$