Solve [(-3)(-3)^2(-3)^3]div[(-3)^2(-3)^3]=

$$[ ( - 3 ) ( - 3 ) ^ { 2 } ( - 3 ) ^ { 3 } ] \div [ ( - 3 ) ^ { 2 } ( - 3 ) ^ { 3 } ] =$$

Evaluate

$$-3$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{\left(-3\right)^{3}\left(-3\right)^{3}}{\left(-3\right)^{2}\left(-3\right)^{3}}$$

To multiply powers of the same base, add their exponents. Add 3 and 3 to get 6.

$$\frac{\left(-3\right)^{6}}{\left(-3\right)^{2}\left(-3\right)^{3}}$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$\frac{\left(-3\right)^{6}}{\left(-3\right)^{5}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 5 from 6 to get 1.

$$\left(-3\right)^{1}$$

Calculate -3 to the power of 1 and get -3.

$$-3$$

Factor

$$-3$$