Solve [(-3)^{6}:(-3)^3]^3*(-3)^0*(-3)^-4=

$$[ ( - 3 ) ^ { 6 } : ( - 3 ) ^ { 3 } ] ^ { 3 } \cdot ( - 3 ) ^ { 0 } \cdot ( - 3 ) ^ { - 4 } =$$

Evaluate

$$-243$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 3 from 6 to get 3.

$$\left(\left(-3\right)^{3}\right)^{3}\left(-3\right)^{0}\left(-3\right)^{-4}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$\left(-3\right)^{9}\left(-3\right)^{0}\left(-3\right)^{-4}$$

To multiply powers of the same base, add their exponents. Add 9 and 0 to get 9.

$$\left(-3\right)^{9}\left(-3\right)^{-4}$$

To multiply powers of the same base, add their exponents. Add 9 and -4 to get 5.

$$\left(-3\right)^{5}$$

Calculate -3 to the power of 5 and get -243.

$$-243$$

Factor

$$-243$$