Solve [(-3)^{6}:(-3)^3]^3,(-3)^0*(-3)^-4

$$[ ( - 3 ) ^ { 6 } : ( - 3 ) ^ { 3 } ] ^ { 3 } , ( - 3 ) ^ { 0 } \cdot ( - 3 ) ^ { - 4 }$$

Sort

$$-19683,\frac{1}{81}$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 3 from 6 to get 3.

$$sort(\left(\left(-3\right)^{3}\right)^{3},\left(-3\right)^{0}\left(-3\right)^{-4})$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$sort(\left(-3\right)^{9},\left(-3\right)^{0}\left(-3\right)^{-4})$$

To multiply powers of the same base, add their exponents. Add 0 and -4 to get -4.

$$sort(\left(-3\right)^{9},\left(-3\right)^{-4})$$

Calculate -3 to the power of 9 and get -19683.

$$sort(-19683,\left(-3\right)^{-4})$$

Calculate -3 to the power of -4 and get \frac{1}{81}.

$$sort(-19683,\frac{1}{81})$$

Convert decimal numbers in the list -19683,\frac{1}{81} to fractions.

$$-19683,\frac{1}{81}$$

Evaluate

$$-19683,\frac{1}{81}$$