Solve [(-3)^3-3*(-2)]div(1/2-1)^2z

$$[ ( - 3 ) ^ { 3 } - 3 \times ( - 2 ) ] \div ( \frac { 1 } { 2 } - 1 ) ^ { 2 } z$$

Evaluate

$$-84z$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$\frac{-27-3\left(-2\right)}{\left(\frac{1}{2}-1\right)^{2}}z$$

Multiply 3 and -2 to get -6.

$$\frac{-27-\left(-6\right)}{\left(\frac{1}{2}-1\right)^{2}}z$$

The opposite of -6 is 6.

$$\frac{-27+6}{\left(\frac{1}{2}-1\right)^{2}}z$$

Add -27 and 6 to get -21.

$$\frac{-21}{\left(\frac{1}{2}-1\right)^{2}}z$$

Subtract 1 from \frac{1}{2} to get -\frac{1}{2}.

$$\frac{-21}{\left(-\frac{1}{2}\right)^{2}}z$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-21}{\frac{1}{4}}z$$

Divide -21 by \frac{1}{4} by multiplying -21 by the reciprocal of \frac{1}{4}.

$$-21\times 4z$$

Multiply -21 and 4 to get -84.

$$-84z$$

Expand

$$-84z$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$\frac{-27-3\left(-2\right)}{\left(\frac{1}{2}-1\right)^{2}}z$$

Multiply 3 and -2 to get -6.

$$\frac{-27-\left(-6\right)}{\left(\frac{1}{2}-1\right)^{2}}z$$

The opposite of -6 is 6.

$$\frac{-27+6}{\left(\frac{1}{2}-1\right)^{2}}z$$

Add -27 and 6 to get -21.

$$\frac{-21}{\left(\frac{1}{2}-1\right)^{2}}z$$

Subtract 1 from \frac{1}{2} to get -\frac{1}{2}.

$$\frac{-21}{\left(-\frac{1}{2}\right)^{2}}z$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-21}{\frac{1}{4}}z$$

Divide -21 by \frac{1}{4} by multiplying -21 by the reciprocal of \frac{1}{4}.

$$-21\times 4z$$

Multiply -21 and 4 to get -84.

$$-84z$$