Solve [(-3)^3divsqrt{9}]-[12div(-2)^2]+sqrt{4^3}=

$$[ ( - 3 ) ^ { 3 } \div \sqrt { 9 } ] - [ 12 \div ( - 2 ) ^ { 2 } ] + \sqrt { 4 ^ { 3 } } =$$

Evaluate

$$-4$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$\frac{-27}{\sqrt{9}}-\frac{12}{\left(-2\right)^{2}}+\sqrt{4^{3}}$$

Calculate the square root of 9 and get 3.

$$\frac{-27}{3}-\frac{12}{\left(-2\right)^{2}}+\sqrt{4^{3}}$$

Divide -27 by 3 to get -9.

$$-9-\frac{12}{\left(-2\right)^{2}}+\sqrt{4^{3}}$$

Calculate -2 to the power of 2 and get 4.

$$-9-\frac{12}{4}+\sqrt{4^{3}}$$

Divide 12 by 4 to get 3.

$$-9-3+\sqrt{4^{3}}$$

Subtract 3 from -9 to get -12.

$$-12+\sqrt{4^{3}}$$

Calculate 4 to the power of 3 and get 64.

$$-12+\sqrt{64}$$

Calculate the square root of 64 and get 8.

$$-12+8$$

Add -12 and 8 to get -4.

$$-4$$

Factor

$$-4$$