Solve [(-3)^3+(-5)^2]*(-5)^2+(-7)^2=

$$[ ( - 3 ) ^ { 3 } + ( - 5 ) ^ { 2 } ] \cdot ( - 5 ) ^ { 2 } + ( - 7 ) ^ { 2 } =$$

Evaluate

$$-1$$

Solution Steps

Calculate -3 to the power of 3 and get -27.

$$\left(-27+\left(-5\right)^{2}\right)\left(-5\right)^{2}+\left(-7\right)^{2}$$

Calculate -5 to the power of 2 and get 25.

$$\left(-27+25\right)\left(-5\right)^{2}+\left(-7\right)^{2}$$

Add -27 and 25 to get -2.

$$-2\left(-5\right)^{2}+\left(-7\right)^{2}$$

Calculate -5 to the power of 2 and get 25.

$$-2\times 25+\left(-7\right)^{2}$$

Multiply -2 and 25 to get -50.

$$-50+\left(-7\right)^{2}$$

Calculate -7 to the power of 2 and get 49.

$$-50+49$$

Add -50 and 49 to get -1.

$$-1$$

Factor

$$-1$$