Solve [(-2)^3]^4div[(-2)^3*(-2)^6]=

$$[ ( - 2 ) ^ { 3 } ] ^ { 4 } \div [ ( - 2 ) ^ { 3 } \cdot ( - 2 ) ^ { 6 } ] =$$

Evaluate

$$-8$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 4 to get 12.

$$\frac{\left(-2\right)^{12}}{\left(-2\right)^{3}\left(-2\right)^{6}}$$

To multiply powers of the same base, add their exponents. Add 3 and 6 to get 9.

$$\frac{\left(-2\right)^{12}}{\left(-2\right)^{9}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 9 from 12 to get 3.

$$\left(-2\right)^{3}$$

Calculate -2 to the power of 3 and get -8.

$$-8$$

Factor

$$-8$$