Solve [(-2)^3]^0*((-2)^2/-2)^2=

$$[ ( - 2 ) ^ { 3 } ] ^ { 0 } \cdot ( \frac { ( - 2 ) ^ { 2 } } { - 2 } ) ^ { 2 } =$$

Evaluate

$$4$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and 0 to get 0.

$$\left(-2\right)^{0}\times \left(\frac{\left(-2\right)^{2}}{-2}\right)^{2}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$\left(-2\right)^{0}\left(\left(-2\right)^{1}\right)^{2}$$

To raise a power to another power, multiply the exponents. Multiply 1 and 2 to get 2.

$$\left(-2\right)^{0}\left(-2\right)^{2}$$

To multiply powers of the same base, add their exponents. Add 0 and 2 to get 2.

$$\left(-2\right)^{2}$$

Calculate -2 to the power of 2 and get 4.

$$4$$

Factor

$$2^{2}$$