Solve [(-2)^-2]^3*(-2)^3*(-2)^4=

$$[ ( - 2 ) ^ { - 2 } ] ^ { 3 } \cdot ( - 2 ) ^ { 3 } \cdot ( - 2 ) ^ { 4 } =$$

Evaluate

$$-2$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -2 and 3 to get -6.

$$\left(-2\right)^{-6}\left(-2\right)^{3}\left(-2\right)^{4}$$

To multiply powers of the same base, add their exponents. Add -6 and 3 to get -3.

$$\left(-2\right)^{-3}\left(-2\right)^{4}$$

To multiply powers of the same base, add their exponents. Add -3 and 4 to get 1.

$$\left(-2\right)^{1}$$

Calculate -2 to the power of 1 and get -2.

$$-2$$

Factor

$$-2$$