Solve [(-1)^3-(-1)^5*(-1)^4]+(-1)^7,9

$$[ ( - 1 ) ^ { 3 } - ( - 1 ) ^ { 5 } \cdot ( - 1 ) ^ { 4 } ] + ( - 1 ) ^ { 7 } , 9$$

Sort

$$-1,9$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 5 and 4 to get 9.

$$sort(\left(-1\right)^{3}-\left(-1\right)^{9}+\left(-1\right)^{7},9)$$

Calculate -1 to the power of 3 and get -1.

$$sort(-1-\left(-1\right)^{9}+\left(-1\right)^{7},9)$$

Calculate -1 to the power of 9 and get -1.

$$sort(-1-\left(-1\right)+\left(-1\right)^{7},9)$$

The opposite of -1 is 1.

$$sort(-1+1+\left(-1\right)^{7},9)$$

Add -1 and 1 to get 0.

$$sort(0+\left(-1\right)^{7},9)$$

Calculate -1 to the power of 7 and get -1.

$$sort(0-1,9)$$

Subtract 1 from 0 to get -1.

$$sort(-1,9)$$

The list values are already in order.

$$-1,9$$

Evaluate

$$-1,9$$