Solve [(-7/3)*4/5-2]*5/3

$$[ ( - \frac { 7 } { 3 } ) \times \frac { 4 } { 5 } - 2 ] \times \frac { 5 } { 3 }$$

Evaluate

$$-\frac{58}{9}\approx -6.444444444$$

Solution Steps

Multiply -\frac{7}{3} times \frac{4}{5} by multiplying numerator times numerator and denominator times denominator.

$$\left(\frac{-7\times 4}{3\times 5}-2\right)\times \frac{5}{3}$$

Do the multiplications in the fraction \frac{-7\times 4}{3\times 5}.

$$\left(\frac{-28}{15}-2\right)\times \frac{5}{3}$$

Fraction \frac{-28}{15} can be rewritten as -\frac{28}{15} by extracting the negative sign.

$$\left(-\frac{28}{15}-2\right)\times \frac{5}{3}$$

Convert 2 to fraction \frac{30}{15}.

$$\left(-\frac{28}{15}-\frac{30}{15}\right)\times \frac{5}{3}$$

Since -\frac{28}{15} and \frac{30}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-28-30}{15}\times \frac{5}{3}$$

Subtract 30 from -28 to get -58.

$$-\frac{58}{15}\times \frac{5}{3}$$

Multiply -\frac{58}{15} times \frac{5}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-58\times 5}{15\times 3}$$

Do the multiplications in the fraction \frac{-58\times 5}{15\times 3}.

$$\frac{-290}{45}$$

Reduce the fraction \frac{-290}{45} to lowest terms by extracting and canceling out 5.

$$-\frac{58}{9}$$

Factor

$$-\frac{58}{9} = -6\frac{4}{9} = -6.444444444444445$$