Solve [(-2/3)^3(-2/3)]-(4/9)^2

$$[ ( - \frac { 2 } { 3 } ) ^ { 3 } ( - \frac { 2 } { 3 } ) ] - ( \frac { 4 } { 9 } ) ^ { 2 }$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$\left(-\frac{2}{3}\right)^{4}-\left(\frac{4}{9}\right)^{2}$$

Calculate -\frac{2}{3} to the power of 4 and get \frac{16}{81}.

$$\frac{16}{81}-\left(\frac{4}{9}\right)^{2}$$

Calculate \frac{4}{9} to the power of 2 and get \frac{16}{81}.

$$\frac{16}{81}-\frac{16}{81}$$

Subtract \frac{16}{81} from \frac{16}{81} to get 0.

$$0$$

Factor

$$0$$