Solve [(-1/3)^2]^3*(-1/9)^-3

$$[ ( - \frac { 1 } { 3 } ) ^ { 2 } ] ^ { 3 } \times ( - \frac { 1 } { 9 } ) ^ { - 3 }$$

Evaluate

$$-1$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$\left(-\frac{1}{3}\right)^{6}\left(-\frac{1}{9}\right)^{-3}$$

Calculate -\frac{1}{3} to the power of 6 and get \frac{1}{729}.

$$\frac{1}{729}\left(-\frac{1}{9}\right)^{-3}$$

Calculate -\frac{1}{9} to the power of -3 and get -729.

$$\frac{1}{729}\left(-729\right)$$

Multiply \frac{1}{729} and -729 to get -1.

$$-1$$

Factor

$$-1$$