Solve [(6/6-5/6)*(-7+1)*(3/6-5)+2]

$$[ ( \frac { 6 } { 6 } - \frac { 5 } { 6 } ) \cdot ( - 7 + 1 ) \cdot ( \frac { 3 } { 6 } - 5 ) + 2 ]$$

Evaluate

$$\frac{13}{2}=6.5$$

Solution Steps

Since \frac{6}{6} and \frac{5}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-5}{6}\left(-7+1\right)\left(\frac{3}{6}-5\right)+2$$

Subtract 5 from 6 to get 1.

$$\frac{1}{6}\left(-7+1\right)\left(\frac{3}{6}-5\right)+2$$

Add -7 and 1 to get -6.

$$\frac{1}{6}\left(-6\right)\left(\frac{3}{6}-5\right)+2$$

Multiply \frac{1}{6} and -6 to get \frac{-6}{6}.

$$\frac{-6}{6}\left(\frac{3}{6}-5\right)+2$$

Divide -6 by 6 to get -1.

$$-\left(\frac{3}{6}-5\right)+2$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$-\left(\frac{1}{2}-5\right)+2$$

Convert 5 to fraction \frac{10}{2}.

$$-\left(\frac{1}{2}-\frac{10}{2}\right)+2$$

Since \frac{1}{2} and \frac{10}{2} have the same denominator, subtract them by subtracting their numerators.

$$-\frac{1-10}{2}+2$$

Subtract 10 from 1 to get -9.

$$-\left(-\frac{9}{2}\right)+2$$

Multiply -1 and -\frac{9}{2} to get \frac{9}{2}.

$$\frac{9}{2}+2$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{9}{2}+\frac{4}{2}$$

Since \frac{9}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{9+4}{2}$$

Add 9 and 4 to get 13.

$$\frac{13}{2}$$

Factor

$$\frac{13}{2} = 6\frac{1}{2} = 6.5$$