Solve [(2/4+1/3)^2:14/12]

$$[ ( \frac { 2 } { 4 } + \frac { 1 } { 3 } ) ^ { 2 } : \frac { 14 } { 12 } ]$$

Evaluate

$$\frac{25}{42}\approx 0.595238095$$

Solution Steps

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{\left(\frac{1}{2}+\frac{1}{3}\right)^{2}}{\frac{14}{12}}$$

Add \frac{1}{2} and \frac{1}{3} to get \frac{5}{6}.

$$\frac{\left(\frac{5}{6}\right)^{2}}{\frac{14}{12}}$$

Calculate \frac{5}{6} to the power of 2 and get \frac{25}{36}.

$$\frac{\frac{25}{36}}{\frac{14}{12}}$$

Reduce the fraction \frac{14}{12} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{25}{36}}{\frac{7}{6}}$$

Divide \frac{25}{36} by \frac{7}{6} by multiplying \frac{25}{36} by the reciprocal of \frac{7}{6}.

$$\frac{25}{36}\times \frac{6}{7}$$

Multiply \frac{25}{36} and \frac{6}{7} to get \frac{25}{42}.

$$\frac{25}{42}$$

Factor

$$\frac{5 ^ {2}}{2 \cdot 3 \cdot 7} = 0.5952380952380952$$