Solve [(11/6)(2/8)]+9/3

$$[ ( \frac { 11 } { 6 } ) ( \frac { 2 } { 8 } ) ] + \frac { 9 } { 3 }$$

Evaluate

$$\frac{83}{24}\approx 3.458333333$$

Solution Steps

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$\frac{11}{6}\times \frac{1}{4}+\frac{9}{3}$$

Multiply \frac{11}{6} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{11\times 1}{6\times 4}+\frac{9}{3}$$

Do the multiplications in the fraction \frac{11\times 1}{6\times 4}.

$$\frac{11}{24}+\frac{9}{3}$$

Divide 9 by 3 to get 3.

$$\frac{11}{24}+3$$

Convert 3 to fraction \frac{72}{24}.

$$\frac{11}{24}+\frac{72}{24}$$

Since \frac{11}{24} and \frac{72}{24} have the same denominator, add them by adding their numerators.

$$\frac{11+72}{24}$$

Add 11 and 72 to get 83.

$$\frac{83}{24}$$

Factor

$$\frac{83}{2 ^ {3} \cdot 3} = 3\frac{11}{24} = 3.4583333333333335$$