Solve [(-1/6)div(-2/3)]^2=

$$[ ( \frac { - 1 } { 6 } ) \div ( - \frac { 2 } { 3 } ) ] ^ { 2 } =$$

Evaluate

$$\frac{1}{16}=0.0625$$

Solution Steps

Divide \frac{-1}{6} by -\frac{2}{3} by multiplying \frac{-1}{6} by the reciprocal of -\frac{2}{3}.

$$\left(\frac{-3}{6\left(-2\right)}\right)^{2}$$

Cancel out 3 in both numerator and denominator.

$$\left(\frac{-1}{-2\times 2}\right)^{2}$$

Multiply -2 and 2 to get -4.

$$\left(\frac{-1}{-4}\right)^{2}$$

Fraction \frac{-1}{-4} can be simplified to \frac{1}{4} by removing the negative sign from both the numerator and the denominator.

$$\left(\frac{1}{4}\right)^{2}$$

Calculate \frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$\frac{1}{16}$$

Factor

$$\frac{1}{2 ^ {4}} = 0.0625$$