Solve [(-1/2)^2+2^-3+(-2)^-2]=

$$[ ( \frac { - 1 } { 2 } ) ^ { 2 } + 2 ^ { - 3 } + ( - 2 ) ^ { - 2 } ] =$$

Evaluate

$$\frac{5}{8}=0.625$$

Solution Steps

Fraction \frac{-1}{2} can be rewritten as -\frac{1}{2} by extracting the negative sign.

$$\left(-\frac{1}{2}\right)^{2}+2^{-3}+\left(-2\right)^{-2}$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{4}+2^{-3}+\left(-2\right)^{-2}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{1}{4}+\frac{1}{8}+\left(-2\right)^{-2}$$

Add \frac{1}{4} and \frac{1}{8} to get \frac{3}{8}.

$$\frac{3}{8}+\left(-2\right)^{-2}$$

Calculate -2 to the power of -2 and get \frac{1}{4}.

$$\frac{3}{8}+\frac{1}{4}$$

Add \frac{3}{8} and \frac{1}{4} to get \frac{5}{8}.

$$\frac{5}{8}$$

Factor

$$\frac{5}{2 ^ {3}} = 0.625$$