Solve [|-3^2+(-3)^3|-(-3)+(-2)*(5-7)]:(-43)

$$[ | - 3 ^ { 2 } + ( - 3 ) ^ { 3 } | - ( - 3 ) + ( - 2 ) \cdot ( 5 - 7 ) ] : ( - 43 )$$

Evaluate

$$-1$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\frac{|-9+\left(-3\right)^{3}|-\left(-3\right)-2\left(5-7\right)}{-43}$$

Calculate -3 to the power of 3 and get -27.

$$\frac{|-9-27|-\left(-3\right)-2\left(5-7\right)}{-43}$$

Subtract 27 from -9 to get -36.

$$\frac{|-36|-\left(-3\right)-2\left(5-7\right)}{-43}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -36 is 36.

$$\frac{36-\left(-3\right)-2\left(5-7\right)}{-43}$$

The opposite of -3 is 3.

$$\frac{36+3-2\left(5-7\right)}{-43}$$

Add 36 and 3 to get 39.

$$\frac{39-2\left(5-7\right)}{-43}$$

Subtract 7 from 5 to get -2.

$$\frac{39-2\left(-2\right)}{-43}$$

Multiply -2 and -2 to get 4.

$$\frac{39+4}{-43}$$

Add 39 and 4 to get 43.

$$\frac{43}{-43}$$

Divide 43 by -43 to get -1.

$$-1$$

Factor

$$-1$$