Solve [8^8/21+9^12/18]*(24/28)^4

$$[ \frac { 8 ^ { 8 } } { 21 } + \frac { 9 ^ { 12 } } { 18 } ] \times ( \frac { 24 } { 28 } ) ^ { 4 }$$

Evaluate

$$\frac{142351734143736}{16807}\approx 8469788430.043196287$$

Solution Steps

Calculate 8 to the power of 8 and get 16777216.

$$\left(\frac{16777216}{21}+\frac{9^{12}}{18}\right)\times \left(\frac{24}{28}\right)^{4}$$

Calculate 9 to the power of 12 and get 282429536481.

$$\left(\frac{16777216}{21}+\frac{282429536481}{18}\right)\times \left(\frac{24}{28}\right)^{4}$$

Reduce the fraction \frac{282429536481}{18} to lowest terms by extracting and canceling out 9.

$$\left(\frac{16777216}{21}+\frac{31381059609}{2}\right)\times \left(\frac{24}{28}\right)^{4}$$

Add \frac{16777216}{21} and \frac{31381059609}{2} to get \frac{659035806221}{42}.

$$\frac{659035806221}{42}\times \left(\frac{24}{28}\right)^{4}$$

Reduce the fraction \frac{24}{28} to lowest terms by extracting and canceling out 4.

$$\frac{659035806221}{42}\times \left(\frac{6}{7}\right)^{4}$$

Calculate \frac{6}{7} to the power of 4 and get \frac{1296}{2401}.

$$\frac{659035806221}{42}\times \frac{1296}{2401}$$

Multiply \frac{659035806221}{42} and \frac{1296}{2401} to get \frac{142351734143736}{16807}.

$$\frac{142351734143736}{16807}$$

Factor

$$\frac{2 ^ {3} \cdot 3 ^ {3} \cdot 13 \cdot 50695062017}{7 ^ {5}} = 8469788430\frac{726}{16807} = 8469788430.043197$$