Solve [4/7+5/2]*[6/2-8/11]

$$[ \frac { 4 } { 7 } + \frac { 5 } { 2 } ] \times [ \frac { 6 } { 2 } - \frac { 8 } { 11 } ]$$

Evaluate

$$\frac{1075}{154}\approx 6.980519481$$

Solution Steps

Least common multiple of 7 and 2 is 14. Convert \frac{4}{7} and \frac{5}{2} to fractions with denominator 14.

$$\left(\frac{8}{14}+\frac{35}{14}\right)\left(\frac{6}{2}-\frac{8}{11}\right)$$

Since \frac{8}{14} and \frac{35}{14} have the same denominator, add them by adding their numerators.

$$\frac{8+35}{14}\left(\frac{6}{2}-\frac{8}{11}\right)$$

Add 8 and 35 to get 43.

$$\frac{43}{14}\left(\frac{6}{2}-\frac{8}{11}\right)$$

Divide 6 by 2 to get 3.

$$\frac{43}{14}\left(3-\frac{8}{11}\right)$$

Convert 3 to fraction \frac{33}{11}.

$$\frac{43}{14}\left(\frac{33}{11}-\frac{8}{11}\right)$$

Since \frac{33}{11} and \frac{8}{11} have the same denominator, subtract them by subtracting their numerators.

$$\frac{43}{14}\times \frac{33-8}{11}$$

Subtract 8 from 33 to get 25.

$$\frac{43}{14}\times \frac{25}{11}$$

Multiply \frac{43}{14} times \frac{25}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{43\times 25}{14\times 11}$$

Do the multiplications in the fraction \frac{43\times 25}{14\times 11}.

$$\frac{1075}{154}$$

Factor

$$\frac{5 ^ {2} \cdot 43}{2 \cdot 7 \cdot 11} = 6\frac{151}{154} = 6.98051948051948$$