Solve [2/3div(-4)-1/4*(-04)]div(1/3)^2-(-2)

$$[ \frac { 2 } { 3 } \div ( - 4 ) - \frac { 1 } { 4 } \times ( - 04 ) ] \div ( \frac { 1 } { 3 } ) ^ { 2 } - ( - 2 )$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Express \frac{\frac{2}{3}}{-4} as a single fraction.

$$\frac{\frac{2}{3\left(-4\right)}-\frac{1}{4}\times 0\times 4}{\left(\frac{1}{3}\right)^{2}}-\left(-2\right)$$

Multiply 3 and -4 to get -12.

$$\frac{\frac{2}{-12}-\frac{1}{4}\times 0\times 4}{\left(\frac{1}{3}\right)^{2}}-\left(-2\right)$$

Reduce the fraction \frac{2}{-12} to lowest terms by extracting and canceling out 2.

$$\frac{-\frac{1}{6}-\frac{1}{4}\times 0\times 4}{\left(\frac{1}{3}\right)^{2}}-\left(-2\right)$$

Multiply \frac{1}{4} and 0 to get 0.

$$\frac{-\frac{1}{6}-0\times 4}{\left(\frac{1}{3}\right)^{2}}-\left(-2\right)$$

Multiply 0 and 4 to get 0.

$$\frac{-\frac{1}{6}-0}{\left(\frac{1}{3}\right)^{2}}-\left(-2\right)$$

Subtract 0 from -\frac{1}{6} to get -\frac{1}{6}.

$$\frac{-\frac{1}{6}}{\left(\frac{1}{3}\right)^{2}}-\left(-2\right)$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{-\frac{1}{6}}{\frac{1}{9}}-\left(-2\right)$$

Divide -\frac{1}{6} by \frac{1}{9} by multiplying -\frac{1}{6} by the reciprocal of \frac{1}{9}.

$$-\frac{1}{6}\times 9-\left(-2\right)$$

Express -\frac{1}{6}\times 9 as a single fraction.

$$\frac{-9}{6}-\left(-2\right)$$

Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{2}-\left(-2\right)$$

The opposite of -2 is 2.

$$-\frac{3}{2}+2$$

Convert 2 to fraction \frac{4}{2}.

$$-\frac{3}{2}+\frac{4}{2}$$

Since -\frac{3}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{-3+4}{2}$$

Add -3 and 4 to get 1.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$