Solve [1/2+(3/4-2)]*(-8)

$$[ \frac { 1 } { 2 } + ( \frac { 3 } { 4 } - 2 ) ] \cdot ( - 8 )$$

Evaluate

$$6$$

Solution Steps

Least common multiple of 2 and 4 is 4. Convert \frac{1}{2} and \frac{3}{4} to fractions with denominator 4.

$$\left(\frac{2}{4}+\frac{3}{4}-2\right)\left(-8\right)$$

Since \frac{2}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$\left(\frac{2+3}{4}-2\right)\left(-8\right)$$

Add 2 and 3 to get 5.

$$\left(\frac{5}{4}-2\right)\left(-8\right)$$

Convert 2 to fraction \frac{8}{4}.

$$\left(\frac{5}{4}-\frac{8}{4}\right)\left(-8\right)$$

Since \frac{5}{4} and \frac{8}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-8}{4}\left(-8\right)$$

Subtract 8 from 5 to get -3.

$$-\frac{3}{4}\left(-8\right)$$

Express -\frac{3}{4}\left(-8\right) as a single fraction.

$$\frac{-3\left(-8\right)}{4}$$

Multiply -3 and -8 to get 24.

$$\frac{24}{4}$$

Divide 24 by 4 to get 6.

$$6$$

Factor

$$2\times 3$$