Solve [(-1)^3/3-2(-1)^2+(-1)]

$$[ \frac { ( - 1 ) ^ { 3 } } { 3 } - 2 ( - 1 ) ^ { 2 } + ( - 1 ) ]$$

Evaluate

$$-\frac{10}{3}\approx -3.333333333$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$\frac{-1}{3}-2\left(-1\right)^{2}-1$$

Fraction \frac{-1}{3} can be rewritten as -\frac{1}{3} by extracting the negative sign.

$$-\frac{1}{3}-2\left(-1\right)^{2}-1$$

Calculate -1 to the power of 2 and get 1.

$$-\frac{1}{3}-2\times 1-1$$

Multiply 2 and 1 to get 2.

$$-\frac{1}{3}-2-1$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{1}{3}-\frac{6}{3}-1$$

Since -\frac{1}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-6}{3}-1$$

Subtract 6 from -1 to get -7.

$$-\frac{7}{3}-1$$

Convert 1 to fraction \frac{3}{3}.

$$-\frac{7}{3}-\frac{3}{3}$$

Since -\frac{7}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-3}{3}$$

Subtract 3 from -7 to get -10.

$$-\frac{10}{3}$$

Factor

$$-\frac{10}{3} = -3\frac{1}{3} = -3.3333333333333335$$