Solve ?=45/6-55/9+21/3-11/18

$$? = 4 \frac { 5 } { 6 } - 5 \frac { 5 } { 9 } + 2 \frac { 1 } { 3 } - \frac { 11 } { 18 }$$

Evaluate

$$1$$

Solution Steps

Multiply 4 and 6 to get 24.

$$\frac{24+5}{6}-\frac{5\times 9+5}{9}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Add 24 and 5 to get 29.

$$\frac{29}{6}-\frac{5\times 9+5}{9}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Multiply 5 and 9 to get 45.

$$\frac{29}{6}-\frac{45+5}{9}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Add 45 and 5 to get 50.

$$\frac{29}{6}-\frac{50}{9}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Least common multiple of 6 and 9 is 18. Convert \frac{29}{6} and \frac{50}{9} to fractions with denominator 18.

$$\frac{87}{18}-\frac{100}{18}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Since \frac{87}{18} and \frac{100}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{87-100}{18}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Subtract 100 from 87 to get -13.

$$-\frac{13}{18}+\frac{2\times 3+1}{3}-\frac{11}{18}$$

Multiply 2 and 3 to get 6.

$$-\frac{13}{18}+\frac{6+1}{3}-\frac{11}{18}$$

Add 6 and 1 to get 7.

$$-\frac{13}{18}+\frac{7}{3}-\frac{11}{18}$$

Least common multiple of 18 and 3 is 18. Convert -\frac{13}{18} and \frac{7}{3} to fractions with denominator 18.

$$-\frac{13}{18}+\frac{42}{18}-\frac{11}{18}$$

Since -\frac{13}{18} and \frac{42}{18} have the same denominator, add them by adding their numerators.

$$\frac{-13+42}{18}-\frac{11}{18}$$

Add -13 and 42 to get 29.

$$\frac{29}{18}-\frac{11}{18}$$

Since \frac{29}{18} and \frac{11}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{29-11}{18}$$

Subtract 11 from 29 to get 18.

$$\frac{18}{18}$$

Divide 18 by 18 to get 1.

$$1$$

Factor

$$1$$