Solve =x(3/5+1/4)-1/4=11/160

$$= x ( \frac { 3 } { 5 } + \frac { 1 } { 4 } ) - \frac { 1 } { 4 } = \frac { 11 } { 160 }$$

Solve for x

$$x=\frac{3}{8}=0.375$$

Steps for Solving Linear Equation

Least common multiple of 5 and 4 is 20. Convert \frac{3}{5} and \frac{1}{4} to fractions with denominator 20.

$$x\left(\frac{12}{20}+\frac{5}{20}\right)-\frac{1}{4}=\frac{11}{160}$$

Since \frac{12}{20} and \frac{5}{20} have the same denominator, add them by adding their numerators.

$$x\times \frac{12+5}{20}-\frac{1}{4}=\frac{11}{160}$$

Add 12 and 5 to get 17.

$$x\times \frac{17}{20}-\frac{1}{4}=\frac{11}{160}$$

Add \frac{1}{4} to both sides.

$$x\times \frac{17}{20}=\frac{11}{160}+\frac{1}{4}$$

Least common multiple of 160 and 4 is 160. Convert \frac{11}{160} and \frac{1}{4} to fractions with denominator 160.

$$x\times \frac{17}{20}=\frac{11}{160}+\frac{40}{160}$$

Since \frac{11}{160} and \frac{40}{160} have the same denominator, add them by adding their numerators.

$$x\times \frac{17}{20}=\frac{11+40}{160}$$

Add 11 and 40 to get 51.

$$x\times \frac{17}{20}=\frac{51}{160}$$

Multiply both sides by \frac{20}{17}, the reciprocal of \frac{17}{20}.

$$x=\frac{51}{160}\times \frac{20}{17}$$

Multiply \frac{51}{160} times \frac{20}{17} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{51\times 20}{160\times 17}$$

Do the multiplications in the fraction \frac{51\times 20}{160\times 17}.

$$x=\frac{1020}{2720}$$

Reduce the fraction \frac{1020}{2720} to lowest terms by extracting and canceling out 340.

$$x=\frac{3}{8}$$