Solve =x*(1+0.012)^1

$$= x \cdot ( 1 + 0.012 ) ^ { 1 }$$

Evaluate

$$\frac{253x}{250}$$

Solution Steps

Add 1 and 0.012 to get 1.012.

$$x\times 1.012^{1}$$

Calculate 1.012 to the power of 1 and get 1.012.

$$x\times 1.012$$

Differentiate w.r.t. x

$$1.012$$

Steps Using Definition of a Derivative

Add 1 and 0.012 to get 1.012.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\times 1.012^{1})$$

Calculate 1.012 to the power of 1 and get 1.012.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\times 1.012)$$

The derivative of ax^{n} is nax^{n-1}.

$$1.012x^{1-1}$$

Subtract 1 from 1.

$$1.012x^{0}$$

For any term t except 0, t^{0}=1.

$$1.012\times 1$$

For any term t, t\times 1=t and 1t=t.

$$1.012$$