Solve for f
f=\frac{\left(x-5\right)\left(x-2\right)\left(x+3\right)}{x}
x\neq 0
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xf=x^{3}-4x^{2}-11x+30
The equation is in standard form.
\frac{xf}{x}=\frac{\left(x-5\right)\left(x-2\right)\left(x+3\right)}{x}
Divide both sides by x.
f=\frac{\left(x-5\right)\left(x-2\right)\left(x+3\right)}{x}
Dividing by x undoes the multiplication by x.
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