Solve =7x^2+8x+

$$= 7 x ^ { 2 } + 8 x +$$

Factor

$$x\left(7x+8\right)$$

Solution Steps

Factor out x.

$$x\left(7x+8\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$7x^{2}+8x=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-8±\sqrt{8^{2}}}{2\times 7}$$

Take the square root of 8^{2}.

$$x=\frac{-8±8}{2\times 7}$$

Multiply 2 times 7.

$$x=\frac{-8±8}{14}$$

Now solve the equation x=\frac{-8±8}{14} when ± is plus. Add -8 to 8.

$$x=\frac{0}{14}$$

Divide 0 by 14.

$$x=0$$

Now solve the equation x=\frac{-8±8}{14} when ± is minus. Subtract 8 from -8.

$$x=-\frac{16}{14}$$

Reduce the fraction \frac{-16}{14} to lowest terms by extracting and canceling out 2.

$$x=-\frac{8}{7}$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 0 for x_{1} and -\frac{8}{7} for x_{2}.

$$7x^{2}+8x=7x\left(x-\left(-\frac{8}{7}\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$7x^{2}+8x=7x\left(x+\frac{8}{7}\right)$$

Add \frac{8}{7} to x by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

$$7x^{2}+8x=7x\times \frac{7x+8}{7}$$

Cancel out 7, the greatest common factor in 7 and 7.

$$7x^{2}+8x=x\left(7x+8\right)$$

Evaluate

$$x\left(7x+8\right)$$